PHP Find alderen

never mind...

fandt denne her istedet:

function getAge($_dob)
{
$dob = date("Y-m-d",strtotime($_dob));
$ageparts = explode("-",$dob);

// calculate age
$age = date("Y-m-d")-$dob;

// return their age (or their age minus one year if it's not their birthday yet, in current year
return (date("nd") < $ageparts[1].str_pad($ageparts[2],2,'0',STR_PAD_LEFT)) ? $age-=1 : $age;
}
$age = getAge('1910/06/20');
echo "you are $age years old";

Den her er også god:

function aar($year,$month,$day) {

$age = ($month > date("m") || ($month == date("m") && $day > date("d"))) ? -1 : 0;
return date("Y") - $year + $age;
}

Og meget simpel! Til at forstå..